59475 Train Schedule | Train Time Table

Train Number
Mahesana Junction to Patan
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STATION NAME STATION CODE ARRIVAL HALT TIME
In Mins
DEPARTURE DAYS DISTANCE
In KMs
Mahesana Jn MSH
Average Delay: (- min)
09:45
Average Delay: (0 min)
1 0.0
Panchot PHC 09:51
Average Delay: (- min)
2m 09:53
Average Delay: (- min)
1 7.1
Dhinoj DHJ 10:01
Average Delay: (0 min)
1m 10:02
Average Delay: (1 min)
1 14.1
Ranuj Jn RUJ 10:15
Average Delay: (1 min)
2m 10:17
Average Delay: (1 min)
1 26.3
Sankhari SNHR 10:25
Average Delay: (- min)
1m 10:26
Average Delay: (- min)
1 31.5
Patan PTN 10:40
Average Delay: (0 min)

Average Delay: (- min)
1 39.8

About Train 59475

Train 59475 runs from Mahesana Junction(MSH) to Patan(PTN) on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Train departs from Mahesana Junction(MSH) at 09:45 and reaches Patan(PTN) at 10:40. It takes 1 day to reach train 59475 from Mahesana Junction(MSH) to Patan(PTN) .

59475 train passes through 6 major stations in 1 day to reach from Mahesana Junction to Patan . It takes total of 0:55 hours journey to reach Patan .

In 59475 train route maximum halt time for this train is 2 minutes at Panchot(PHC). Train 59475 arrives at Panchot at 09:51 and departs at 09:53. So if you want to get down from the train and buy anything from the station or for little fresh air. It's safe to get down at this station.


59475 FAQ

From which station train 59475 starts from?

59475 starts from Mahesana Junction(MSH)

How many days in a week 59475 runs ?

59475 runs on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday,

What is the maximum halt time of 59475 and at which station?

Maximum halt time of 59475 train is 2 minutes at Panchot(PHC)

Top Train Routes related to 59475

For more information on 59475 train Click IRCTC